In this type of program we always find how many column present in a particular row. Because we know that we are always print in VDU horizontally. Here column number is same as (row number * 2 ) - 1 and the spacces are present at the right side of the character is equal to the (total no of row - current row). It is Pyramid which 1st row is A, 2nd row in B and so on.
#include <stdio.h> void main() { int r,c,n,s; printf("Enter Total Number of row : "); scanf("%d",&n); for(r=1;r<=n;r++) { for(s=1;s<=n-r;s++) { printf(" "); } for(c=1;c<=2*r-1;c++) { printf("%c",r+64); } printf("\n"); } }
Enter Total Number of row : 6
A BBB CCCCC DDDDDDD EEEEEEEEE FFFFFFFFFFF